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$\frac{(100 - 1)(100 - 2)(100 - 3). . .(100- 200)}{100\times 99\times 98\times . . .\times 3\times 2\times 1}$is equal to1). $\frac{100}{99\times 98\times 97\times . . .\times 3\times 2\times 1}$2). $-\frac{1}{99\times 98\times 97\times . . .\times 3\times 2\times 1}$3). 04). $\frac{2}{99\times 98\times 97\times . . .\times 3\times 2\times 1}$ |
Answer» ANSWER for this QUESTION is OPTION 3 | |