1.

$\frac{12}{3+\sqrt{5}+2\sqrt{2}}$ is equal to1). $1-\sqrt{5}+\sqrt{2}+\sqrt{10}$2). $1+\sqrt{5}+\sqrt{2}-\sqrt{10}$3). $1+\sqrt{5}-\sqrt{2}+\sqrt{10}$4). $1-\sqrt{5}-\sqrt{2}+\sqrt{10}$

Answer»

I am not sure, may be $1+\SQRT{5}+\sqrt{2}-\sqrt{10}$ is CORRECT



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