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\frac { 16 \times 2 ^ { n + 1 } - 4 \times 2 ^ { n } } { 16 \times 2 ^ { n + 2 } - 2 \times 2 ^ { n + 2 } } |
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Answer» 4(2^(n+3)-2^n)/4(2^(n+4)-2^n)=2^n(2^3-1)/2^n(2^4-1)=7/15 |
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