\(\frac{17}{15}\times\)\(\frac{17}{15}+\)\(\frac{2}{15}\times\)\(\frac

1.	\(\frac{17}{15}\times\)\(\frac{17}{15}+\)\(\frac{2}{15}\times\)\(\frac{2}{15}-\)\(\frac{17}{15}\times\)\(\frac4{15}\) is equal to(a) 0 (b) 1 (c) 10 (d) 11
Answer» (b) 1 Given exp. = \(\frac{17}{15}\times\)\(\frac{17}{15}+\)\(\frac{2}{15}\times\)\(\frac{2}{15}-\)2 x \(\frac{17}{15}\times\)\(\frac{2}{15}\) = \(\big(\frac{17}{15}\big)^2\) + \(\big(\frac{2}{15}\big)^2\) - 2 x \(\frac{17}{15}\times\)\(\frac{2}{15}\) = \(\big(\frac{17}{15}-\frac{2}{15}\big)^2\) [Using a² + b² - 2ab = (a - b)²] = \(\big(\frac{15}{15}\big)^2\) = 1² = 1

\(\frac{17}{15}\times\)\(\frac{17}{15}+\)\(\frac{2}{15}\times\)\(\frac{2}{15}-\)\(\frac{17}{15}\times\)\(\frac4{15}\) is equal to(a) 0 (b) 1 (c) 10 (d) 11

Answer»

(b) 1

Given exp. = \(\frac{17}{15}\times\)\(\frac{17}{15}+\)\(\frac{2}{15}\times\)\(\frac{2}{15}-\)2 x \(\frac{17}{15}\times\)\(\frac{2}{15}\)

= \(\big(\frac{17}{15}\big)^2\) + \(\big(\frac{2}{15}\big)^2\) - 2 x \(\frac{17}{15}\times\)\(\frac{2}{15}\)

= \(\big(\frac{17}{15}-\frac{2}{15}\big)^2\) [Using a² + b² - 2ab = (a - b)²]

= \(\big(\frac{15}{15}\big)^2\) = 1² = 1