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\frac { 3 } { 2 } \operatorname { log } 4 - \frac { 2 } { 3 } \operatorname { log } 8 + \operatorname { log } _ { 2 } = \operatorname { log } x |
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Answer» 2/3log4-2/3log8+log2=log(2^2)^2/3-(log2^3)^2/3+log2=log2^4/3-log2^2+log2=log((2^4/3×2)/2^2)=log(2^(8/3-2))=log(2^2/3)so x=2^(2/3) |
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