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\frac { 4 ^ { 2 n } \cdot 2 ^ { n + 1 } } { 2 ^ { n - 3 } \cdot 4 ^ { 2 n + 1 } }

Answer»

4^(2n)×2^(n+1)----------------------2^(n-3) × 4^(2n+1)

2^(4n) × 2^(n+1)= ------------------------ 2^(n-3) × 2^(4n+2)

= 2^ { 4n+n+1-(n-3+4n+2)}

= 2^ { 5n+1-5n +1}= 2^2 = 4


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