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\((\frac{4}{3})^{-2}\) = .................A) \(\frac{9}{16}\)B) \(\frac{14}{3}\)C) \(\frac{16}{9}\)D) \(\frac{9}{17}\) |
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Answer» Correct option is (A) 9/16 \((\frac{4}{3})^{-2}=\left[(\frac{4}{3})^{-1}\right]^2=(\frac34)^2\) \(=\frac{3^2}{4^2}=\frac{9}{16}\) Correct option is A) \(\frac{9}{16}\) |
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