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\(\frac{4a^2-1}{2a+1}\) = .....................A) a – 1 B) a +1 C) 2a D) 2a – 1 |
Answer» Correct option is D) 2a – 1 Correct option is (D) 2a – 1 \(\frac{4a^2-1}{2a+1}=\frac{(2a)^2-1}{2a+1}=\frac{(2a+1)(2a-1)}{(2a+1)}\) = 2a – 1 |
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