1.

\( \frac{5}{x}-2 y=\frac{17}{3} \) \( \frac{2}{x}+3 y=\frac{-16}{3}, x \neq 0 \)

Answer»

\(\frac5x-2y=\frac{17}3\)---(1)

\(\frac2x+3y=\frac{-16}3\)---(2), \(\neq\) 0

By doing, 3 x (1) + 2 x (2), we obtain

\((\frac{15}x-6y) + (\frac yx+6y) = \frac{51}3-\frac{32}3\)

⇒ \(\frac{19}x=\frac{19}3\)

x = 3

∴ 5/3 - 2y = 17/3

⇒ 2y = 5/3 - 17/3 = -12/3 = -4

y = -2



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