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\( \frac{5}{x}-2 y=\frac{17}{3} \) \( \frac{2}{x}+3 y=\frac{-16}{3}, x \neq 0 \) |
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Answer» \(\frac5x-2y=\frac{17}3\)---(1) \(\frac2x+3y=\frac{-16}3\)---(2), x \(\neq\) 0 By doing, 3 x (1) + 2 x (2), we obtain \((\frac{15}x-6y) + (\frac yx+6y) = \frac{51}3-\frac{32}3\) ⇒ \(\frac{19}x=\frac{19}3\) ⇒ x = 3 ∴ 5/3 - 2y = 17/3 ⇒ 2y = 5/3 - 17/3 = -12/3 = -4 ⇒ y = -2 |
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