\(\frac{6}{7}- \frac{5}{4}-\frac{1}{3} \) x + 2x = 0 then x = .......

1.	\(\frac{6}{7}- \frac{5}{4}-\frac{1}{3} \) x + 2x = 0 then x = ...................A) \(\frac{133}{196}\)B) \(\frac{1}{194}\)C) \(\frac{3}{196}\)D) none
Answer» Correct option is D) none Correct option is (D) none \(\frac{6}{7}-\frac{5}{4}-\frac{1}{3}\)x + 2x = 0 \(\Rightarrow\) \(2x-\frac x3=\frac{5}{4}-\frac67\) \(\Rightarrow\) \(\frac{6x-x}3=\frac{5\times7-6\times4}{4\times7}\) \(\Rightarrow\) \(\frac{5x}3=\frac{35-24}{28}=\frac{11}{28}\) \(\Rightarrow\) \(x=\frac{11}{28}\times\frac35=\frac{33}{28\times5}=\frac{33}{140}.\)

\(\frac{6}{7}- \frac{5}{4}-\frac{1}{3} \) x + 2x = 0 then x = ...................A) \(\frac{133}{196}\)B) \(\frac{1}{194}\)C) \(\frac{3}{196}\)D) none

Answer»

Correct option is D) none

Correct option is (D) none

\(\frac{6}{7}-\frac{5}{4}-\frac{1}{3}\)x + 2x = 0

\(\Rightarrow\) \(2x-\frac x3=\frac{5}{4}-\frac67\)

\(\Rightarrow\) \(\frac{6x-x}3=\frac{5\times7-6\times4}{4\times7}\)

\(\Rightarrow\) \(\frac{5x}3=\frac{35-24}{28}=\frac{11}{28}\)

\(\Rightarrow\) \(x=\frac{11}{28}\times\frac35=\frac{33}{28\times5}=\frac{33}{140}.\)