1.

\(\frac{(a^2-b^2)^3+(b^2-c^2)^3 + (c^2-a^2)^3}{(a-b)^3+(b-c)^3+(c-a)^3}\) on simplification is equal to :(a) 1 (b) (a – b) (b – c) (c – a) (c) (a + b) (b + c) (c + a) (d) 0

Answer»

(c) (a + b) (b + c) (c + a) 

Use the identity, if a + b + c = 0, then a3 + b3 + c3 = 3abc.



Discussion

No Comment Found