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\frac{\cos ^{2}\left(\frac{\pi}{4}-A\right)-\sin ^{2}\left(\frac{\pi}{4}-A\right)}{\cos ^{2}\left(\frac{\pi}{4}+A\right)+\sin ^{2}\left(\frac{\pi}{4}+A\right)}= |
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Answer» cos^2A-sin^2A=cos2Acos^2A+isn^2A=1hencehencecos(π/4-A+π/4-A)cos(π/2-2A)sin(2A) |
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