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\frac { \cos 58 } { \sin 32 } + \frac { \sin 22 } { \cos 68 } - \frac { \cos 38 \csc 52 } { \tan 18 \tan 35 \tan 60 \tan 72 \tan 55 } |
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Answer» cos58°= sin32° as cos(90-theta) = sin thetatan(90-theta)= cot thetasintheta= 1/cosec theta |
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