\(\frac{d}{dx}\)\([\sqrt{\frac{secx -1}{secx+1}}]\) =d/dx[√((sec x -1)/(sec x +1)) =(A) sec2\(\frac{x}{2}\)(B) \(\frac{1}{2}\)sec2\(\frac{x}{2}\)(C) tan\(\frac{x}{2}\)(D) \(\frac{1}{2\sqrt{sec^2x+1}}\)

\(\frac{d}{dx}\)\([\sqrt{\frac{secx -1}{secx+1}}]\) =d/dx[√((sec x

1.	\(\frac{d}{dx}\)\([\sqrt{\frac{secx -1}{secx+1}}]\) =d/dx[√((sec x -1)/(sec x +1)) =(A) sec2\(\frac{x}{2}\)(B) \(\frac{1}{2}\)sec2\(\frac{x}{2}\)(C) tan\(\frac{x}{2}\)(D) \(\frac{1}{2\sqrt{sec^2x+1}}\)
Answer» Option : (B) \(\frac{1}{2}\)sec²\(\frac{x}{2}\)

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\(\frac{d}{dx}\)\([\sqrt{\frac{secx -1}{secx+1}}]\) =d/dx[√((sec x -1)/(sec x +1)) =(A) sec2\(\frac{x}{2}\)(B) \(\frac{1}{2}\)sec2\(\frac{x}{2}\)(C) tan\(\frac{x}{2}\)(D) \(\frac{1}{2\sqrt{sec^2x+1}}\)

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