1.

$\frac{\sqrt[3]{8}}{\sqrt{16}}+\sqrt{\frac{100}{49}}\times \sqrt[3]{125}$ is equal to :1). 72). $1\frac{3}{4}$3). $\frac{7}{100}$4). $\frac{4}{7}$

Answer»

I have READ it SOMEWHERE $1\frac{3}{4}$ is CORRECT



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