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\frac{\tan 66^{\circ}+\tan 69^{\circ}}{1-\tan 66^{\circ} \cdot \tan 69^{\circ}} |
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Answer» formula is (tan x + tan y) =tan x +tan y 1-tan x tan y therefore; Tan X = 69 and Tan Y = 66 . by substituting values of x and y in the formula, we get Tan(69+66)= Tan(135) tan(135) is 1*180*(-45) So tan -45 value is -1 =tan(a+b)=tan(66+69)=tan135'=tan(90+45)=-tan45=-1 |
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