\(\frac{x+2}{x-2} = \frac{7}{3}\) then x = .................x+2/x-2 =

1.	\(\frac{x+2}{x-2} = \frac{7}{3}\) then x = .................x+2/x-2 = 7/3 then x = ............A) 5B) -5C)1D) 6
Answer» Correct option is A) 5 Correct option is (A) 5 \(\frac{x+2}{x-2}=\frac{7}{3}\) \(\Rightarrow\) 3(x+2) = 7(x-2) \(\Rightarrow\) 3x+6 = 7x - 14 \(\Rightarrow\) 7x - 3x = 6+14 \(\Rightarrow\) 4x = 20 \(\Rightarrow\) \(x=\frac{20}4=5.\) Alternative \(\frac{x+2}{x-2}=\frac{7}{3}\) \(\Rightarrow\) \(\frac{(x+2)+(x-2)}{(x+2)-(x-2)}=\frac{7+3}{7-3}\) \(\Rightarrow\) \(\frac{2x}4=\frac{10}4\) \(\Rightarrow\) 2x = 10 \(\Rightarrow\) \(x=\frac{10}2=5.\)

\(\frac{x+2}{x-2} = \frac{7}{3}\) then x = .................x+2/x-2 = 7/3 then x = ............A) 5B) -5C)1D) 6

Answer»

Correct option is A) 5

Correct option is (A) 5

\(\frac{x+2}{x-2}=\frac{7}{3}\)

\(\Rightarrow\) 3(x+2) = 7(x-2)

\(\Rightarrow\) 3x+6 = 7x - 14

\(\Rightarrow\) 7x - 3x = 6+14

\(\Rightarrow\) 4x = 20

\(\Rightarrow\) \(x=\frac{20}4=5.\)

Alternative \(\frac{x+2}{x-2}=\frac{7}{3}\)

\(\Rightarrow\) \(\frac{(x+2)+(x-2)}{(x+2)-(x-2)}=\frac{7+3}{7-3}\)

\(\Rightarrow\) \(\frac{2x}4=\frac{10}4\)

\(\Rightarrow\) 2x = 10

\(\Rightarrow\) \(x=\frac{10}2=5.\)