InterviewSolution
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\(\frac{x^3+y^3+z^3-3xyz}{a^3+b^3+c^3-3abc}\times\frac{a^2+b^2+c^2-ab-bc-ca}{x^2+y^2+z^2-xy-yz-zx}\) equlas(a) 1 (b) \(\frac{x^2+y^2+z^2}{a^2+b^2+c^2}\)(c) \(\frac{x+y+z}{a+b+c}\)(d) \(\frac{xyz}{abc}\) |
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Answer» (c) \(\frac{x+y+z}{a+b+c}\) Reqd. exp. = \(\frac{(x+y+z)(x^2+y^2+z^2-xy-yz-zx)}{(a+b+c)(a^2+b^2+c^2-ab-bc-ca)}\times\frac{a^2+b^2+c^2-ab-bc-ca}{x^2+y^2+z^2-xy-yz-zx}\) = \(\frac{x+y+z}{a+b+c}\) |
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