\(\frac{x-4}{7} - \frac{(x+4)}{5} = \frac{x+3}{7}\) then x = ........

1.	\(\frac{x-4}{7} - \frac{(x+4)}{5} = \frac{x+3}{7}\) then x = .........................x-4/7 - (x+4)/5 = x+3/7 then x = .........................A) 14 B) 7 C) 9 D) – 9
Answer» Correct option is D) – 9 Correct option is (D) – 9 \(\frac{x-4}{7}-\frac{x+4}{5}=\frac{x+3}{7}\) \(\Rightarrow\) \(\frac{5(x-4)-7(x+4)}{35}=\frac{x+3}{7}\) \(\Rightarrow\) 5x - 20 - 7x - 28 = 35 \(\times\frac{x+3}{7}\) \(\Rightarrow\) -2x - 48 = 5x + 15 \(\Rightarrow\) 5x + 2x = -48 - 15 = -63 \(\Rightarrow\) 7x = -63 \(\Rightarrow\) x = \(\frac{-63}7\) = -9.

\(\frac{x-4}{7} - \frac{(x+4)}{5} = \frac{x+3}{7}\) then x = .........................x-4/7 - (x+4)/5 = x+3/7 then x = .........................A) 14 B) 7 C) 9 D) – 9

Answer»

Correct option is D) – 9

Correct option is (D) – 9

\(\frac{x-4}{7}-\frac{x+4}{5}=\frac{x+3}{7}\)

\(\Rightarrow\) \(\frac{5(x-4)-7(x+4)}{35}=\frac{x+3}{7}\)

\(\Rightarrow\) 5x - 20 - 7x - 28 = 35 \(\times\frac{x+3}{7}\)

\(\Rightarrow\) -2x - 48 = 5x + 15

\(\Rightarrow\) 5x + 2x = -48 - 15 = -63

\(\Rightarrow\) 7x = -63

\(\Rightarrow\) x = \(\frac{-63}7\) = -9.