1.

\frac{x}{7}=\frac{y}{3}=\frac{3 x+5 y}{\ldots \ldots}=\frac{7 x-9 y}{\ldots \ldots}

Answer»

suppose x/3=y/7=kso x=3k and y=7kso 3x+5y=3(3k)+5(7k)=44kso 44now 7x-9y=21k-63k=-42kso -42



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