1.

Fraction of total power carried by the side bands (PS/PT) is given bym^2(2+m^2)/m^2(2+m)/mm^2/(2+m^2)

Answer» Fraction of total power carried by the side bands (PS/PT) is given by
m^2
(2+m^2)/m^2
(2+m)/m
m^2/(2+m^2)


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