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Fraction of total power carried by the side bands (PS/PT) is given bym^2(2+m^2)/m^2(2+m)/mm^2/(2+m^2) |
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Answer» Fraction of total power carried by the side bands (PS/PT) is given by m^2 (2+m^2)/m^2 (2+m)/m m^2/(2+m^2) |
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