Frequency of a particle executing SHM is 10 Hz. The particle is suspended from a vertical spring. At the highest point of its oscillation the spring is unstretched. Find the maximum speed of the particle : (g= 10m//s^(2))

Frequency of a particle executing SHM is 10 Hz. The particle is suspen

1.	Frequency of a particle executing SHM is 10 Hz. The particle is suspended from a vertical spring. At the highest point of its oscillation the spring is unstretched. Find the maximum speed of the particle : (g= 10m//s^(2))
Answer» Solution :Mean position of the particle is `(mg)/(k)` distance below unstretched position of SPRING. THEREFORE, amplitude of oscillation is `A= (mg)/(k) OMEGA= sqrt((k)/(m))= 2pif= 20pi` `:. (m)/(k)= (1)/(400pi^(2))` Therefore, the maximum speed of particle will be: `v_("max")= Aomega= ((g)/(400pi^(2)))(20pi)= (1)/(2pi)m//s`