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Friedel Craft’s reaction using CH3COCl/AlCl3 is not successful in case of : (a) C6H5CH3 (b) C6H5NO2 (c) C6H5OH (d) C6H6

Answer» <p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>Correct option (b) C<sub>6</sub>H<sub>5</sub>NO<sub>2</sub></strong></span></span></p><p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>Explanation:</strong></span></span></p><p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif">Friedel Craft’s reaction using CH<sub>3</sub>COCl/AlCl<sub>3</sub> is not successful in the case of C<sub>6</sub>H<sub>5</sub>NO<sub>2 </sub>because —NO<sub>2 </sub>deactivate the ring for Friedel Craft’s reaction (Electrophilic substitution).</span></span></p>


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