From 320 mg. of `O_(2), 6.023 xx 10^(20)` molecules are removed, the no. of moles remained areA. `9 xx 10^(-3)` molesB. `9 xx 10^(-2)` molesC. ZeroD. `3 xx 10^(-3)` moles

From 320 mg. of `O_(2), 6.023 xx 10^(20)` molecules are removed, the n

1.	From 320 mg. of `O_(2), 6.023 xx 10^(20)` molecules are removed, the no. of moles remained areA. `9 xx 10^(-3)` molesB. `9 xx 10^(-2)` molesC. ZeroD. `3 xx 10^(-3)` moles
Answer» Correct Answer - A No. of moles of `(Wt)/(M.Wt)` or `("No. of molecules")/(N)`

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From 320 mg. of `O_(2), 6.023 xx 10^(20)` molecules are removed, the no. of moles remained areA. `9 xx 10^(-3)` molesB. `9 xx 10^(-2)` molesC. ZeroD. `3 xx 10^(-3)` moles

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