From 320 mg. of O2, 6.023 × 1020 molecules are removed, the no. of mo – InterviewSolution

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1.	From 320 mg. of O2, 6.023 × 1020 molecules are removed, the no. of moles remained are
Answer» From 320 mg. of $O_{2}$ , $6.023 \times 10^{20}$ molecules are removed, the no. of moles remained are

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