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From a circular disc of radius R and mass 9 M , a small disc of radius R/3 is removed from the disc. The moment of inertia of the remaining disc about an axis perpendicular to the plane of the disc and passing through O is A. `8 mR^(2)`B. `4 mR^(2)`C. `(40)/(9) mR^(2)`D. `(37)/(9) mR^(2)` |
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Answer» Correct Answer - B `I_("remaining") = I_("whole") - I_("removed")` `I =(1)/(2) (9m) (R^(2)) -[(1)/(2)m ((R)/(3))^(2) + m((2R)/(3))^(2)]` `I = 4mR^(2)`. |
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