From a circular sheet of radius 5 cm a circle of radius 3 cm is remove

1.	From a circular sheet of radius 5 cm a circle of radius 3 cm is removed. Find the area of the remaining sheet.
Answer» Radius of the outer circle R = 5 cm Radius of the inner circle r = 3 cm Area of the remaining sheet = Area of the outer circle – Area of the inner circle = πR² – πr² sq. units = π(R² – r²) sq. units = \(\frac{22}{7}\)(5² – 3²) cm² = \(\frac{22}{7}\) x (5 + 3) (5 – 3) = \(\frac{22}{7}\) x (8) (2) = \(\frac{352}{7}\) = 50.28 cm²

From a circular sheet of radius 5 cm a circle of radius 3 cm is removed. Find the area of the remaining sheet.

Answer»

Radius of the outer circle R = 5 cm

Radius of the inner circle r = 3 cm

Area of the remaining sheet = Area of the outer circle – Area of the inner circle

= πR² – πr² sq. units

= π(R² – r²) sq. units

= \(\frac{22}{7}\)(5² – 3²) cm²

= \(\frac{22}{7}\) x (5 + 3) (5 – 3)

= \(\frac{22}{7}\) x (8) (2)

= \(\frac{352}{7}\)

= 50.28 cm²