From a given sample of uniform wire, two circular loops moment of inertia of O about its axis is 4 times that of P about its axis (assuming wire diameter much smaller, than either radius), the value of n is

From a given sample of uniform wire, two circular loops moment of iner

1.	From a given sample of uniform wire, two circular loops moment of inertia of O about its axis is 4 times that of P about its axis (assuming wire diameter much smaller, than either radius), the value of n is
Answer» `(4)^(2//3)` `(4)^(1//3)` `(4)^(1//2)` `(4)^(1//4)` Solution :Given `I_(Q) = 4 I_(P)` Here I = mass `XX "(radius)"^(2)` If `MU` be the linear mass density (mass/length) of the wire , then `mu xx 2pi (n r) xx n^(2) r^(2) = 4 (mu xx 2pi r xx r^(2))` On SOLVING , we get `n^(3) = 4` or `n = (4)^(1//3)`