from a point on the30°. Find the speed of flyingA bird is sitting on

1.	from a point on the30°. Find the speed of flyingA bird is sitting on the top of a tree, which is 80 m high. The angle of elevation of theground is 45. The bird flies away from the point of observatioground is 45°. The bird fies away from the point of observation horizontally and reb2 seconds, the angle of elevation of the bird from the point of observation becomes 3e a constant heiof the bird.
Answer» In triangle OAC tan 45=AC/OA=1 AC=OA=80 IN TRIANGLE ODB tan 30=BD/OB=1/√ 3 OB=BD√ 3-AC√ 3(since ac=bd as bird remains constant height) AB=OB-OA=AC√ 3-AC=AC(√ 3-1)=80(√ 3-1) NOW FOR 2 SEC 80(√ 3-1)/2=40(√ 3-1) =29.2M/SEC

from a point on the30°. Find the speed of flyingA bird is sitting on the top of a tree, which is 80 m high. The angle of elevation of theground is 45. The bird flies away from the point of observatioground is 45°. The bird fies away from the point of observation horizontally and reb2 seconds, the angle of elevation of the bird from the point of observation becomes 3e a constant heiof the bird.

Answer»

In triangle OAC tan 45=AC/OA=1

AC=OA=80

IN TRIANGLE ODB

tan 30=BD/OB=1/√ 3

OB=BD√ 3-AC√ 3(since ac=bd as bird remains constant height)

AB=OB-OA=AC√ 3-AC=AC(√ 3-1)=80(√ 3-1)

NOW FOR 2 SEC

80(√ 3-1)/2=40(√ 3-1)

=29.2M/SEC