From a solid sphere of mass M and radius R/2aspherical portion of radius ž is romoved as shown in figure. Taking gravitational potential V = 0 and r = oo , the potential at the centre of the cavity thus form is ......... . (G = Gravitational constant)

From a solid sphere of mass M and radius R/2aspherical portion of radi

1.	From a solid sphere of mass M and radius R/2aspherical portion of radius ž is romoved as shown in figure. Taking gravitational potential V = 0 and r = oo , the potential at the centre of the cavity thus form is ......... . (G = Gravitational constant)
Answer» `(-GM)/(2R)` `(-GM)/(R)` `(-2GM)/(3R)` `(-2GM)/(R)` Solution :`implies` Gravitational POTENTIAL of EARTH (SPHERE) is `V_1 = - (GM)/(2R^3) [ 3R^2 -R^2/4] ""...(1)` and Gravitational POTENITAL of portion `R/2` `V_2 =-((3GM)/8)/(2(R/2))` Now , `V = V_1 -V_2` `=-(3GM)/(2R) +(GM)/(8R) +(3GM)/(8R)` `=- (12GM + GM + 3GM)/(8R)` ` = - (8GM)/ (8R)` `= - (GM)/R`