1.

From all two-digit numbers with either digit 1, 2 or 3 one number is chosen. i. What is the probability of both digits being the same? ii. What is the probability of the sum of the digits being 4?

Answer»

Two digit numbers

11, 12, 13, 21, 22, 23, 31, 32, 33.

i. P (both digits being same) = \(\frac{3}{9}=\frac{1}{3}\)

ii. P(sum of digits being 4) = \(\frac{3}{9}=\frac{1}{3}\)



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