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From all two-digit numbers with either digit 1, 2 or 3 one number is chosen. i. What is the probability of both digits being the same? ii. What is the probability of the sum of the digits being 4? |
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Answer» Two digit numbers 11, 12, 13, 21, 22, 23, 31, 32, 33. i. P (both digits being same) = \(\frac{3}{9}=\frac{1}{3}\) ii. P(sum of digits being 4) = \(\frac{3}{9}=\frac{1}{3}\) |
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