From kinetic theory of gases, show that Moon cannot have atmosphere (Assume k=1.38xx10^(-23)JK^(-1),T0^@C=273K).

From kinetic theory of gases, show that Moon cannot have atmosphere (A

1.	From kinetic theory of gases, show that Moon cannot have atmosphere (Assume k=1.38xx10^(-23)JK^(-1),T0^@C=273K).
Answer» Solution :We KNOW that `1/2mV^2_(rms)=3/2kT` `:.V_(rms) = sqrt((3kT)/m)` mass = `3.33xx10^(-27)kg` Temperature = 0+273=273K Boltzmann constant `k = 1.38xx10^(-23)J//K` `:.V_(rms)=sqrt((3xx1.38xx10^(-23)xx273)/(3.33xx10^(-27)))` `= sqrt((3xx1.38xx273)/(3.33)xx10^4)` `=18.422xx10^2` `V_(rms) =1.842xx10^3ms^(-1)` The value of `v_e` is less than the velocity of gass present on mon . HENCE MOON cannot have an ATMOSPHERE.