From The First Floor of Qutab Minar which is at a height of 25 m Fru

1.	From The First Floor of Qutab Minar which is at a height of 25 m Frum the a man angle observes a. level ground the top of a building at an of elevation of 30 depression of the base of and the angle of the building to be 60° Calculate the height of the building.
Answer» Let the height of the first floor of Qutub Minar be AB = EC = 25 m And DEC (DC) be the height of the tower. BC = AE = Distance between their bases ∠DAE be the angle of elevation of the top of the building. ∠EAC be the angle of depression of the base of the building. In triangle EAC, Tan ∠EAC = EC/AE => √3 = 25/AE => AE = 25/√3 meters In triangle ADE, Tan ∠DAE = DE/AE => 1/√3 = DE/25/√3 => 3DE = 25 => DE = 25/3 => DE = 8.33 approx Height of the building = DE + EC = 8.33 + 25 = 33.33 meters approx. Thus, the height of the building = 33.33 metres.

From The First Floor of Qutab Minar which is at a height of 25 m Frum the a man angle observes a. level ground the top of a building at an of elevation of 30 depression of the base of and the angle of the building to be 60° Calculate the height of the building.

Answer»

Let the height of the first floor of Qutub Minar be AB = EC = 25 m

And DEC (DC) be the height of the tower.

BC = AE = Distance between their bases

∠DAE be the angle of elevation of the top of the building.

∠EAC be the angle of depression of the base of the building.

In triangle EAC,

Tan ∠EAC = EC/AE

=> √3 = 25/AE

=> AE = 25/√3 meters

In triangle ADE,

Tan ∠DAE = DE/AE

=> 1/√3 = DE/25/√3

=> 3DE = 25

=> DE = 25/3

=> DE = 8.33 approx

Height of the building = DE + EC = 8.33 + 25 = 33.33 meters approx.

Thus, the height of the building = 33.33 metres.

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