From the following bond energies H-H bond energy : 431.37 kJ `mol^(-1)` C=C bond energy : 606.10 kJ `mol^(-1)` C-C bond energy : 336.49 kJ `mol^(-1)` C-H bond energy : 410.50 kJ `mol^(-1)` Enthalpy for the reaction. `underset(H)underset(|)overset(H)overset(|)(C)=underset(H)underset(|)overset(H)overset(|)(C)+H-HrarrH-underset(H)underset(|)overset(H)overset(|)(C)-underset(H)underset(|)overset(H)overset(|)(C)-H` will beA. 1523.6 kJ `mol^(-1)`B. `-243.6 kJ mol^(-1)`C. `-120.0 kJ mol^(-1)`D. 553.0 kJ `mol^(-1)`

From the following bond energies H-H bond energy : 431.37 kJ `mol^(-1)

1.	From the following bond energies H-H bond energy : 431.37 kJ `mol^(-1)` C=C bond energy : 606.10 kJ `mol^(-1)` C-C bond energy : 336.49 kJ `mol^(-1)` C-H bond energy : 410.50 kJ `mol^(-1)` Enthalpy for the reaction. `underset(H)underset(\|)overset(H)overset(\|)(C)=underset(H)underset(\|)overset(H)overset(\|)(C)+H-HrarrH-underset(H)underset(\|)overset(H)overset(\|)(C)-underset(H)underset(\|)overset(H)overset(\|)(C)-H` will beA. 1523.6 kJ `mol^(-1)`B. `-243.6 kJ mol^(-1)`C. `-120.0 kJ mol^(-1)`D. 553.0 kJ `mol^(-1)`
Answer» Correct Answer - C `[(4xx410.5)xx606.1+431.3)]-[(6xx410.5)+336.49)]` `=-120.0 kJ mol^(-1)`.

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