From the following data at constant volume for combustion of benzene, calculate the heat of this reaction at constant pressure condition. C_6H_(6(l)) +7 1/2O_(2(g)) to 6CO_(2(g)) +3H_2O_((l)) DeltaU at 25^@C =-3268.12 kJ

From the following data at constant volume for combustion of benzene,

1.	From the following data at constant volume for combustion of benzene, calculate the heat of this reaction at constant pressure condition. C_6H_(6(l)) +7 1/2O_(2(g)) to 6CO_(2(g)) +3H_2O_((l)) DeltaU at 25^@C =-3268.12 kJ
Answer» SOLUTION :Given `T=25^@C`=298 K `DeltaU=-3268.12 "KJ MOL"^(-1)` `DeltaH` = ? `DeltaH=DeltaU+Deltan_gRT` `DeltaH=DeltaU+(n_p-n_r)RT` `DeltaH=-3268.12+(6 -7/2)xx8.314xx10^(-3) xx298` `DeltaU=-3268.12+(2.5xx8.314xx10^(-3)xx298)` `DeltaU`=-3268.12+6.19 `DeltaU`=-3261.93 kJ `mol^(-1)`