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From the following data at constant volume for combustion of benzene, calculate the heat of this reaction at constant pressure condition. C_(6)H_(6(1))+71//2O_(2(g))rarr 6CO_(2(g))+13H_(2)O_((l)) |
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Answer» Solution :`DeltaE_(25^(@)C)=-781.1 kcal` `DeltaH=DELTAE+DeltangRT` `DeltaE=-781.1K.cal` `Deltan_(g)=6-71//2=-1.5` `(-1.5)xx1.987xx298` `DeltaH=(-781.1+)/(1000)` `=-781.1-0.888` `therefore DeltaH=-782k.cal` |
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