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From the following data, compute Karl Pearson coefficient of correlation : Summation of product of deviation of X and Y series from their respective means is 46 |
Answer» <html><body><p></p>Solution :We are given <br/> `N=7,bar(X)=4,bar(Y)=<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>,<a href="https://interviewquestions.tuteehub.com/tag/sumx-3819684" style="font-weight:bold;" target="_blank" title="Click to know more about SUMX">SUMX</a>^(2)=<a href="https://interviewquestions.tuteehub.com/tag/28-299271" style="font-weight:bold;" target="_blank" title="Click to know more about 28">28</a>,sumy^(2)=76,sumxy=<a href="https://interviewquestions.tuteehub.com/tag/46-317673" style="font-weight:bold;" target="_blank" title="Click to know more about 46">46</a>` <br/> `r=(sumxy)/(sqrt(sumx^(2)xxsumy^(2)))` <br/> Substituting the values, we get <br/> `r=(46)/(sqrt(28xx76))=(46)/(sqrt(2,128))=(46)/(sqrt(46.13))=0.997` <br/>Coefficient of Correlation (r)=0.997</body></html> | |