From the following data of Deltah, of the following reactions, a. C(s) +1//2O_(2)(g) rarr CO(g),DeltaH^(Theta) =- 110 kJ b. C(s) +H_(2)O(g) rarr CO(g)+H_(2)(g), DeltaH^(Theta) = 132 kJ Calculate the mole composition of the mixture of steam and oxygen on being passed over coke at 1273K, keeping the tempertaure constant.

From the following data of Deltah, of the following reactions, a. C(s

1.	From the following data of Deltah, of the following reactions, a. C(s) +1//2O_(2)(g) rarr CO(g),DeltaH^(Theta) =- 110 kJ b. C(s) +H_(2)O(g) rarr CO(g)+H_(2)(g), DeltaH^(Theta) = 132 kJ Calculate the mole composition of the mixture of steam and oxygen on being passed over coke at 1273K, keeping the tempertaure constant.
Answer» Solution :The first reaction is exothermic and SECOND one is endothermic. If a MIXTURE of STEAM and `O_(2)` is passed over heated coke, and the temperature is KEPT constant, the conversion of each of `CO` should not show any heat change, i.e. heat evolved in reaction (a) = total heat absorbed in reaction (b). `[(1)/(2) "mol of" O_(2) = 110 KJ, n_(1) "mol of" =(110 xx n_(1))/(1//2)]` `:. n_(1) xx 2 xx 110 = n_(2) xx 132` `(n_(1))/(n_(2)) = (132)/(2xx110) = (0.6)/(1)` where `n_(1)` and `n_(2)` are moles of `O_(2)` and `H_(2)O`, respectively, used during reaction: `(n_(2))/(n_(1)) = (1)/(0.6) = 1.66`