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From the following date , mark the opation(s) where `Delta H` is correctly written for the given reaction . Given: `H+(aq) +OH-(aq) to H_(2)O(l),` `DeltaH=-57.3 kJ` `DeltaH_(solution) HA(g)=-70.7 kJ"mole"` `DeltaH_(solution) BOH(g)=- 20 kJ"mole"` `DeltaH_("ionzatoin") ` of `HA=15 kJ//"mole"` and BOH is a strong base. A. `{:("Reaction",DeltaH_r(kJ//"mol")),((A)HA(aq)+BOH(aq)toBA(aq)+H_2O,-42.3):}`B. `{:("Reaction",DeltaH_r(kJ//"mol")),((B)HA(g)+BOH(g)toBA(aq)+H_2O,-93):}`C. `{:("Reaction",DeltaH_r(kJ//"mol")),((C )HA(g)toH^+(aq)+A^(-)(aq),-55.7):}`D. `{:("Reaction",DeltaH_r(kJ//"mol")),((D )B^+(aq)+OH^(-) ("aq"),-20):}` |
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Answer» Correct Answer - ABC (D)BOH(g)+aqueous `to B^+ (aq)+OH^(-)(aq) " " DeltaH=-20` kJ/mole |
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