From the following redox reaction, 2S_(2)O_(3)^(-2)+I_(2)toS_(4)O_(6)

1.	From the following redox reaction, 2S_(2)O_(3)^(-2)+I_(2)toS_(4)O_(6)^(-2)+2I^(-)
Answer» `S_(4)O_(6)^(-2)` is oxidation in `S_(2)O_(3)^(-2)`. `S_(4)O_(6)^(-2)` is redaction in `S_(2)O_(3)^(-2)`. `I_(2)` is REDUCED to `I^(-)`. `I_(2)` is oxidised in `I^(-)`. Solution :`I_(2)` is reduced into `I^(-)`. Here `S_(2)O_(3)^(-2)` is oxidise in `S_(4)O_(6)^(-2)` while `I_(2)` is reduce in `I^(-)`.

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