From the following which compound shows different oxidation number of H ? LiAlH_(4),NaBH_(4),NaHCO_(3),MgH_(2)

From the following which compound shows different oxidation number of

1.	From the following which compound shows different oxidation number of H ? LiAlH_(4),NaBH_(4),NaHCO_(3),MgH_(2)
Answer» `MgH_(2)` `NaHCO_(3)` `LiAlH_(4)` `NaBH_(4)` SOLUTION :`MgH_(2),LiAlH_(4)andNaBH_(4)` are metal HALIDE, so oxidation number of H is -1 and `NaHCO_(3)` is normal compound, so oxidation number of H is (+1).