1.

From the given figure, find the length ofhypotenuse AC and the perimeter of AABC.

Answer»

ABC is right angled triangle

AB² + BC² = AC²

20² + 21² = AC²

AC² = 400 + 441 = 841

AC² = 841 = 29²

AC = 29

So, Perimeter of triangle

20 + 21 + 29

= 41 +29

= 70



Discussion

No Comment Found