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From the given figure, find the length ofhypotenuse AC and the perimeter of AABC. |
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Answer» ABC is right angled triangle AB² + BC² = AC² 20² + 21² = AC² AC² = 400 + 441 = 841 AC² = 841 = 29² AC = 29 So, Perimeter of triangle 20 + 21 + 29 = 41 +29 = 70 |
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