1.

From the rate expressions for the following reactions, determine their order :(a) 2N2O5(g) → 4NO2(g) + O2(g) : Rate = k [N2O5](b) CHCl3(g) + Cl2(g) → CCl4(g) + HCl(g) : Rate = k [CHL3] [Cl2]1/2(c) C2H5Cl(g) → C2H4(g) + HCl(g) : Rate = k [C2H5Cl](d) 2NO2(g) + F2(g) → 2NO2F(g) : Rate = k [NO2] [F2]

Answer»

(a) 2N2O5(g) → 4NO2(g) + O2(g)

The rate law expression given for the reaction is,

Rate = k x [N2O5]

Hence,

The reaction is of first order.

(b) CHCl3(g) + Cl2(g) → CCl4(g) + HCl(g)

The given rate law expression is, 

R = k [CHCl3] x [Cl2]1/2

Here,

The order of a reaction is one with respect to CHCl3(g) and half with respect to Cl2(g).

Therefore,

The overall order of the reaction is 1 + 1/2 = 1.5.

(c) C2H5Cl(g) → C2H4(g) + HCl(g)

The given rate law expression is, 

Rate = k[C2H5Cl]

Hence,

The reaction has order equal to one.

(d) 2NO2(g) + F2(g) → 2NO2F(g)

The given rate law expression for the reaction is,

Rate = k[NO2] [F2]

Hence,

The reaction is first order with respect to NO2 and first order with respect to F2.

The overall order of the reaction is,

n = \(n_{NO_2}\) + nF1 = 1 + 1 = 2.



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