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From the set of all families having three children, a family is picked at random If one child of the family is a son. find the probablilty that he has two sisters. |
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Answer» Solution :The ONE child of the FAMILY is a son. We have to find the probability that he has two sisters. We have the following mutually exclusive EVENTS : BGG,GBG,GGB. `THEREFORE` The required probability `=P(B)xxP(G)xxP(G)+P(G)xxP(B)+P(G)+P(G)xxP(G)xxP(B)` `=1/2xx1/2xx1/2+1/2xx1/2xx1/2+1/2xx1/2xx1/2=3/8` |
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