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From the sum of 5x + 7y -12 and 3x – 5y + 2, subtract the sum of 2x – 7y – 1 and – 6x + 3y + 9. |
Answer» Sum of 5x + 7y – 12 and 3x – 5y + 2. = 5x + 7y- 12 + 3x – 5y + 2 = (5 + 3) x + (7 – 5) y + ((- 12) + 2) = 8x + 2y – 10. Again Sum of 2x – 7y – 1 and – 6x + 3y + 9 = 2x – 7y – 1 + (- 6x + 3y + 9) = 2x – 7y – 1 – 6x + 3y + 9 = (2 – 6) x + (- 7 + 3) y + (- 1 + 9) = – 4x – 4y + 8 Now 8x + 2y – 10 – (-4x – 4y + 8) = 8x + 2y – 10 + (4x + 4y – 8) = 8x + 2y – 10 + 4x + 4y – 8 = (8 + 4) x + (2 + 4) y + ((- 10) + (- 8)) = 12x + 6y – 18 |
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