From the thermochemical equation, C_(6)H_(6)(l) + 7(1)/(2) O_(2)(g) rarr3H_(2)O(l) + 6CO_(2)(g) , Delta_(c ) H = -3264.64kJ mol^(-1) calculate the energy evolved when39 g of C_(6)H_(6) are burnt in an open container.

From the thermochemical equation, C_(6)H_(6)(l) + 7(1)/(2) O_(2)(g) ra

1.	From the thermochemical equation, C_(6)H_(6)(l) + 7(1)/(2) O_(2)(g) rarr3H_(2)O(l) + 6CO_(2)(g) , Delta_(c ) H = -3264.64kJ mol^(-1) calculate the energy evolved when39 g of C_(6)H_(6) are burnt in an open container.
Answer» Solution :From the given EQUATION. When 1 mole of `C_(6)H_(6)(78G ` of `C_(6)H_(6))` is burnt, heat EVOLVED `= 3264.64kJ ` `:. `When 39 G of `C_(6)H_(6)`is burnt, heat evolved`= ( 3264.64)/(78) xx 39 = 1632.32kJ`