From the top of a tower, a particle is thrown vertically downwards with a velocity of 10 m/s. The ratio of distances covered by it in the 3rd and 2nd seconds of its motion is (Take g=10 m/s2)

From the top of a tower, a particle is thrown vertically downwards wit

1.	From the top of a tower, a particle is thrown vertically downwards with a velocity of 10 m/s. The ratio of distances covered by it in the 3rd and 2nd seconds of its motion is (Take g=10 m/s2)
Answer» From the top of a tower, a particle is thrown vertically downwards with a velocity of $10 m / s$ . The ratio of distances covered by it in the $3^{r d}$ and $2^{n d}$ seconds of its motion is (Take $g = 10 m / s^{2}$ )

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From the top of a tower, a particle is thrown vertically downwards with a velocity of 10 m/s. The ratio of distances covered by it in the 3rd and 2nd seconds of its motion is (Take g=10 m/s2)

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