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From the top of a tower, a stone is thrown up and it reaches the ground in time t1. A second stone is thrown down with the same speed and it reaches the ground in time t2. A third stone is released from rest and it reaches the ground in time t3.(a) t3 = 1/2 (t1 + t2)(b) t3 = √ t1t2(c) 1/t3 = 1/t2 - 1/t1(d) t32 = t12 - t22 |
Answer» Correct answer is: (b) t3 = √ t1t2 |
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