From the top of a tower a stone is thrown up which reaches the ground in time t_(1). A second stone thrown down with the same speed reaches the ground in a time t_(2). A third stone released from rest from the same location reaches the ground in a time t_(3). then:

From the top of a tower a stone is thrown up which reaches the ground

1.	From the top of a tower a stone is thrown up which reaches the ground in time t_(1). A second stone thrown down with the same speed reaches the ground in a time t_(2). A third stone released from rest from the same location reaches the ground in a time t_(3). then:
Answer» `(1)/(t_(3)) = (1)/(t_(1)) + (1)/(t_(2))` `t_(3)^(2) = t_(1)^(2) - t_(2)^(2)` `t_(3) = (t_(1) + t_(2))/(2)` `t_(3) = sqrt(t_(1) t_(2))` Solution :`-H = ut_(1) - (1)/(2) g t_(1)^(2)` `H = u t_(2) + (1)/(2) g t_(2)^(2)` `H = (1)/(2) g t_(3)^(2)`