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frons = 212_25th Rind the valueSatralying Roses - Rr 2 3 41). |
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Answer» Given f(x) = x^2 - 3x + 4 Then,f(2x + 1) = (2x+1)^2 - 3(2x+1) + 4= 4x^2 + 1 + 4x - 6x - 3 + 4= 4x^2 - 2x + 2 As per given conditionf(x) = f(2x + 1)x^2 - 3x + 4 = 4x^2 - 2x + 23x^2 + x - 2 = 03x^2 + 3x - 2x - 2 = 03x(x + 1) - 2(x + 1) = 0(3x - 2)(x + 1) = 0x = 2/3, - 1 |
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